Fenton氧化破解剩余污泥的实验研究
Experimental study on excess sludge disintegration by Fenton oxidation
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摘要: 研究了利用Fenton氧化破解污泥，并以SCOD、TOC、TSS和VSS的变化来表征剩余污泥破解程度。结果表明：pH 2.0，H2O2和Fe2+投加量分别为9.0 g/L和0.8 g/L，反应时间1.5 h，反应温度60℃为Fenton氧化破解污泥的最佳反应条件。该条件下，TSS由8.14 g/L减少到5 g/L，TSS去除率为38.57%；污泥上清中的SCOD和TOC的浓度分别由49.6 mg/L和6.3 mg/L 上升到1 726.8 mg/L和796.2 mg/L；污泥的平均粒径和中值粒径分别由原污泥的42.5 μm和36.10 μm减小到24.10 μm和18.07 μm；SVI由115.28 mL/g下降到71.94 mL/g。Fenton氧化法能有效破解污泥，提高污泥的沉降性，改善污泥的脱水性，有利于污泥的减量化与资源化利用。Abstract: The disruption of excess sludge by Fenton oxidation was studied, and the parameters of soluble chemical oxygen demand (SCOD), total organic carbon (TOC), total suspended solid (TSS) and volatile suspended solid (VSS) were selected to characterize the disruption effect. Based on the experimental results,the operation conditions were optimized with pH of 2.0, H2O2 dosage of 9.0 g/L, Fe2+ dosage of 0.8 g/L, reaction time of 1.5 h, and reaction temperature of 60℃, respectively. The value of TSS decreased from 8.14 g/L to 5.0 g/L,the removal efficiencies of TSS was 38.57%. The values of SCOD and TOC in the supernatant increased to 1 726.8 mg/L and 796.2 mg/L from 49.6 mg/L and 6.3 mg/L, respectively. The average particulate diameter and the median particulate diameter of sludge changed from 42.5 μm and 36.10 μm to 24.10 μm and 18.07 μm, respectively. The sludge volume index (SVI) decreased from 115.28 mL/g to 71.94 mL/g.Fenton oxidation was an effective method for sludge reduction with the improvement of sludge settleability and dewatering properties.
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